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1/5=5^2^c^+^3
We move all terms to the left:
1/5-(5^2^c^+^3)=0
We get rid of parentheses
-5^2^c^-^3+1/5=0
We multiply all the terms by the denominator
-5^2^c^*5+1-^3*5=0
We add all the numbers together, and all the variables
-5^2^c^*5=0
Wy multiply elements
-25c^2=0
a = -25; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-25)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$c=\frac{-b}{2a}=\frac{0}{-50}=0$
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